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The molar mass of the solute sodium hydr...

The molar mass of the solute sodium hydrdoxide obtained from the measurement of the osmotic pressure of its aqueous solution at `27^(@)C` is `25 g mol^(-1)`. Therefore its ionization percentage in this solution is

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The correct Answer is:
60
`i=M_c/M_0=40/25=1.6`
`{:(NaOH rarr,Na^(+) ,+OH^(-)),(1 mol,0,0),(1-alpha,alpha,alpha):}` Total `=1+alpha`
`i=1+alpha` or `alpha=i-1=0.6 =60%`
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