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The vapour pressure of water at 20^(@) i...

The vapour pressure of water at `20^(@)` is `17.5 mmHg`. If `18 g` of glucose `(C_(6)H_(12)O_(6))` is added to `178.2 g` of water at `20^(@) C`, the vapour pressure of the resulting solution will be

A

15.750 mm Hg

B

16.500 mm Hg

C

17.325 mm Hg

D

17.675 mm Hg

Text Solution

Verified by Experts

The correct Answer is:
C
`(P^@-P_s)/(P^@)=n/(n+N)`
`n =18/180=0.1,N = (178.2)/(18)=9.9`
`(175-P_s)/(17.5)=(0.1)/(0.1+9.9),(17.5-p_s)/(17.5) =1/100`
1750 - 100 `p_s` =17.5, 1732.5 =100 `p_s`
`p_s` =17.325 mm Hg.
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