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At room temperature, a dilute solution o...

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea `=60 g "mol"^(-1)`)

A

0.027 mmHg

B

0.028 mmHg

C

0.017 mmHg

D

0.031mmHg

Text Solution

Verified by Experts

The correct Answer is:
C
`(P^0-P_s)/(P^0)=n/(n+N)`
Lowering in V.P. `=P^0xxn/(n+N)`
`=35xx((0.6)/60)/((0.6)/60+360/18)=0.017` mm of Hg.
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