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Liquids A and B form an ideal solution i...

Liquids A and B form an ideal solution in the entire composition range. At 350K, the vapor pressure of pure A and pure B are `7xx10^(3)` Pa and `12xx10^(3)` Pa, respectively. The composition of the vapor in equilibrium with a solution containing 40 mole percent of A at this temperature is :

A

`x_A = 0.28, x_B = 0.72`

B

`x_A = 0.76, x_B = 0.24`

C

`x_A = 0.37, x_B = 0.63`

D

`x_A = 0.4, x_B = 0.6`

Text Solution

Verified by Experts

The correct Answer is:
A
`x_A/x_B=(P_A^0x._A)/(P_B^0x._B)=(7xx10^3(0.4))/(12xx10^3(0.6))=28/72=7/18`
`x._A and x._B` are mole fraction in liquid state
`x_A=7/25=0.28 , x_B=18/25=0.72`
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