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The elevation in boiling point of a solu...

The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:

A

`0.16`

B

`0.05`

C

`0.1 `

D

`0.2`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT_b = i.K_b.m`
`CuCl_(2) rarr Cu^(2+) +2Cl^(-)`
`{:(1,0,0),((1-alpha),alpha,2alpha):}`
`i=1+2alpha`
Assuming 100% ionization
So, i = 3
`DeltaT_6 = 3xx 0.52 xx0.1 = 0.156 ~~ 0.16.`
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