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Henry’s constant (in kbar) for four gase...

Henry’s constant (in kbar) for four gases `alpha, beta, gamma and delta` in water at 298 K is given below :

`("density of water = 103 kg m"^(-3)" at 298 K")`
This table implies that :

A

`alpha` has the highest solubility in water at a given pressure

B

Solubility of `gamma` at 308K is lower than at 298 K

C

The pressure of a 55.5 molal solution of `delta` is 1 bar

D

The pressure of a 55.5 molal solution of `delta` 250 bar

Text Solution

Verified by Experts

The correct Answer is:
D

(a) `K_H uarr` solubility `uarr` and lowest `K_H` is for `gamma` .
(b) On increasing temperature solubility of gases decreases.
(c) `P_(gamma) = K_HX_(gamma)`
`P_r=2xx10^(-15)xx(55.5)/(55.5+1000/18)=2xx10^(-5)` Kbar
`=2xx10^(-2)` bar
(d) `P_(delta)=K_HX_(delta)`
`P_(delta)=0.5xx(55.5)/(55.5+1000/18)=0.249 ` Kbar
= 249 bar
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