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1 Kg of an aqueous solution of sucrose i...

`1` Kg of an aqueous solution of sucrose is cooled and maintained at `-4^(@)"C"`. How much ice will be separated out if the molality of the solution is `0.75` m ? `"K"_("F")("H"_(2)"O")=1.86"Kg mol"^(-1)"K"`

Text Solution

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The correct Answer is:
518
Molality of sucrose solution = 0.75 m
Mass of sucrose `= 0.75xx342 g = 256.5g`
Mass of solutions = 1256.5g
Mass of sucrose in 1 kg solution
`=(256.5 xx1000)/(1256.5)= 204.1g`
Mass of water in 1 kg solution = 1000 - 204.1
= 795.9 g
After cooling the solution to `-4^@C`
`4= (1.86 xx 204.1xx1000)/(342xxW_B)=277.5g`
( `W._B` is the mass of water left)
Mass of ice separated = 795.9-277.5
`= 518.4~~518 g`
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