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SF2, SF4 and SF6 have the hybridizations...

`SF_2, SF_4 and SF_6` have the hybridizations at sulphur atom respectively, as

A

`sp^2, sp^3, sp^2 d^2`

B

`sp^3, sp^3, sp^3d^2`

C

`sp^3, sp^3 d , sp^3 d^2`

D

`sp^3, spd^2, d62 sp^3`

Text Solution

Verified by Experts

The correct Answer is:
C

To determine type of hybridization, count `sigma` bonds + `(to)` coordinate bonds + lone pairs on central atom + single electron.
This number comes out to be
`2 to sp` hybridization
`3 to sp^2` hybridization
`4 to sp^3 or dsp^2` hybridization
`5 to sp^3 d` hybridization
`6 to sp^3 d^2 or d^2 sp^3` hybridization
`SF_2 : F - underset(* *)overset(* *) S - F`
Total number ` = 4 to sp^3` hybridization
`SF_4:`
Total number `= 5 to sp^3` d hybridization
`SF_6`:
Total number ` = 6 to sp^3 d^2` hybridization.
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