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The dipole moment of HBr is 1.6 xx 10^...

The dipole moment of `HBr` is ` 1.6 xx 10^(-30) cm` and interatomic spacing is `1 Å`. The `%` ionic character of `HBr` is

A

7

B

10

C

15

D

27

Text Solution

Verified by Experts

The correct Answer is:
B
Charge of `e^(-) = 1.6 xx 10^(-19)`
Dipole moment of `HBr = 1.6 xx 10^(-30)`
Inter atomic spacing `= 1Å = 1 xx 10^(-10) m`
% of ionic character in
`HBr = ("dipole moment of "HBr xx 100)/("inter spacing distance" xxq)`
` = (1.6 xx 10^(-30))/(1.6 xx 10^(-19) xx 10^(-10)) xx 100`
` = 10^(-3) xx 10^(29) xx 100 = 10^(-1) xx 100 = 0.1 xx 100 = 10%`
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