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Given : Dipole moment of HCl=1.03 D Bo...

Given : Dipole moment of `HCl=1.03` D
Bond length =127pm
Dipole moment of `HI=0.38D`
Bond length `=161`pm
The ratio of partial positive charge on H-aotm in HCl to that in HI will be

A

`12 : 1 `

B

`2.7 : 1 `

C

`3.3 : 1 `

D

`1 : 3.3 `

Text Solution

Verified by Experts

The correct Answer is:
C
Dipole moment `mu = deltaxx` bond length
`delta_1 xx 1.3(10^(-10)) = 1.03`
`delta_2 xx 1.6(10^(-10)) = 0.38`
`delta_1/(delta_2) = (3.3 xx10^(-10))/(1xx10^(-10))`
`delta_1 : delta_2 = 3.3 :1`
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