For AB bond if percent ionic character is plotted against electro nehativity difference `(X_A-X_B)`, the shape of the curve would look like

Options

A. (A)
B. (B)
C. (C)
D. (D)

Answer

C

Explanation

Percent ionic character is given by
% of ionic character ` = 16(X_A- X_B) + 3.5 (X_A - X_B)^2`
From the above relation, it is clear that as soon as `(X_A - X_B)` increases, % ionic character will also increase. Therefore, curve C show a correct path.