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Arrange the following ions in the order ...

Arrange the following ions in the order of decreasing `X-O` bond length where X is the central atom:

A

`ClO_4^(-), SO_4^(2-), PO_4^(3-), SiO_4^(4-)`

B

`SiO_4^(4-), PO_4^(3-), SO_4^(2-), ClO_4^(-)`

C

`SiO_4^(4-), PO_4^(3-), ClO_4^(-) ClO_4^(-)`

D

`SiO_4^(4-), SO_4^(2-), PO_4^(3-), ClO_4^(-)`

Text Solution

Verified by Experts

The correct Answer is:
B

Bond order = 1
Ions as increasing bond order :
`SiO_4^(4-) lt PO_4^(3-) lt SO_4^(2-) lt ClO_4^(-)`
Bond length decreases as bond order increases.
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