The hydrogen bonds are encountered in `HF, H_2 O, NH_3` and `HF_2^-`. The relative order of energies of hydrogen bonds is

Options

A. `HF gt H_2O gtH_3N gt HF_2^(-)`
B. `H_2O gt HF_2^(-) gt HF gt NH_3`
C. `HF gt HF_2^(-) gt H_2O gt NH_3`
D. `HF_2^(-) gt HF gt H_2O gt NH_3`

Answer

D

Explanation

Higher is the electronegativity, stronger is the H-bond. Fluorine has more electronegativity among the given compounds. In `HF_2^(-)` there are two fluorine atoms that results into even stronger H -bonding.