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H-B- H bond angle in BH4^- is :...

H-B- H bond angle in `BH_4^-` is :

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The correct Answer is:
109
Boron-hydride ion `(BH_4^(-))` is formed by the `sp^3` hybridization of boron orbitals. Therefore, it is a tetrahedral structure. Thus bond angle is 109.
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