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CH(3)CHOO((1))+C(2)H(5)OH((1))hArrCH(3)C...

`CH_(3)CHOO_((1))+C_(2)H_(5)OH_((1))hArrCH_(3)COOC_(2)H_(5(1))+H_(2)O_((1))` In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. `H_(2)SO_(4).` On equlibrium being attained

A

1 mole of ethyl acetate is formed

B

2 mole of ethyl acetate are formed

C

1/2 moles of ethyl acetate is formed

D

2/3 moles of ethyl acetate is formed

Text Solution

Verified by Experts

The correct Answer is:
D
In presence of little `H_2SO_4` (as catalyst) about 2/3 mole of each of `CH_3COOH and C_2H_5OH` react to form 2/3 mole of the product at equilibrium.
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