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120g of urea is present in 5L of solutio...

120g of urea is present in 5L of solution, the active mass of urea is

A

`0.2 `

B

`0.06`

C

` 0.4 `

D

`0.08`

Text Solution

Verified by Experts

The correct Answer is:
C
Active mass `=("Moles")/L`
`= ("Wt. in molecular wt.")/("V in L") = (120//60)/5 = 2/5 =0.4`
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