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One mole of N(2)O(4) is heated in a flas...

One mole of `N_(2)O_(4)` is heated in a flask with a volume of `10dm^(3).` At equilibrium `1.708` mole of `NO_(2)` and 0.146 mole of `N_(2)O_(4)` were found at `134^(@)C.` The equilibrium constnt will be

A

`250 "mol dm"^(-3)`

B

`300 "mol dm"^(-3)`

C

`2 "mol dm"^3`

D

`230 "mol dm"^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`N_2O_4 hArr 2NO_2`
`{:("Moles at eqb"^m,0.146,1.708),(underset("mol/dm"^3)(Conc).,[(0.146)/10], [(1.708)/10]):}`
`:. K_c =([NO_2]^2)/([N_2O_4])=([(1.708)/(10)]^(2))/([(0.146)/(10)])`
`implies K_c=(2.917264)/(100)xx10/(0.146)`
`implies K_c = (2.917264)/(1.46) = 2 "mol dm"^(-3)`
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