Home
Class 11
CHEMISTRY
For the reaction H2 +I2 hArr 2HI, the eq...

For the reaction `H_2 +I_2 hArr 2HI`, the equilibrium concentration of `H_2,I_2` and HI are 8.0, 3.0 and 28.0 mol per litre respectively, the equilibrium constant of the reaction

A

`30.66 `

B

`32.66`

C

`34.66`

D

`36.66`

Text Solution

Verified by Experts

The correct Answer is:
B

`K_C =([HI]^2)/([H_2][I_2])=((28)^2)/(8xx3) =32.66`
Promotional Banner

Similar Questions

Explore conceptually related problems

Equilibrium concentration of HI, I_(2) and H_(2) is 0.7, 0.1 and 0.1 M respectively. The equilibrium constant for the reaction, I_(2)+H_(2)hArr 2HI is :

In the reaction, H_(2)(g)+I_(2)(g)hArr2HI(g) The concentration of H_(2), I_(2) , and HI at equilibrium are 8.0, 3.0 and 28.0 mol per L respectively. Determine the equilibrium constant.

On a given condition, the equilibrium concentration of H, H_(2) and I_(2) are 0.80 , 0.10 and 0.10 mole/litre. The equilibrium constant for the reaction H_(2) + I_(2) hArr 2HI will be

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) The equilibrium constant K_(p) changes with