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Two moles of NH(3) when put into a provi...

Two moles of `NH_(3)` when put into a proviously evacuated vessel (one litre) pertially dissociate into `N_(2)` and `H_(2)`. If at equilibrium one mole of `NH_(3)` is present, the equilibrium constant is

A

`3//4 "mol"^2 "litre"^(-2)`

B

`27//64 "mol"^2 "litre"^(-2)`

C

`27//32 "mol"^2 "litre"^(-2)`

D

`27//16 "mol"^2 "litre"^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`2NH_3 hArr N_2 +3H_2`
`{:("Initial concentration",2,0,0),("At equilibrium concentration",1,1//2,3//2):}`
`K_c = ([N_2]\[H_2]^3)/([NH_3]^2)=(1//2xx[3//2]^3)/(1^2)=27/16`
[Given `2 - 2x = 1 , 2x = 1 , x = 1//2` ]
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