Home
Class 11
CHEMISTRY
56 g of nitrogen and 8 g hydrogen gas ar...

56 g of nitrogen and 8 g hydrogen gas are heated in a closed vessel. At equilibrium 34 g of ammnia are present. The equilibrium number of moles of nitrogen, hdregen and ammonia are respectively

A

`1,2,2`

B

`2,2,1 `

C

`1,1,2 `

D

`2,1,2 `

Text Solution

Verified by Experts

The correct Answer is:
C
`N_2 +3H_2 hArr 2NH_3 " ".....(i)`
at `{:(t= 0 ,56 g, 8g ,0g),(=,2 "mole",4"mole",0"mole"):}`
at equilibrium 2 -1 4 - 3 `" "` 34g
=1mole = 1mole = 2mole
According to eq. (i) 2 mole of ammonia are present & to produce 2 mole of `NH_3` , we need 1 mole of `N_2` and 3 mole of `H_2` hence 2 - 1 = 1 mole of `N_2 and 4 = 3 = 1` mole of `H_2` are present at equilibrium in vessel.
Promotional Banner

Similar Questions

Explore conceptually related problems

The number of moles of nitrogen atom in 56 g nitrogen is

4.5 moles each of hydrogen and iodine heated in a sealed 10 litrevesel. At equilibrium, 3 moles of HI was foun. The equilibrium constant for H_(2)(g) + I_(2) (g)hArr2HI(g) is

The number of atoms present in 1 g of hydrogen gas is the same as are present in

56 g of nitrogen and 96 g of oxygen are mixed isothermaly and at a total pressure of 10 atm. The partial pressures of oxygen and nitrogen (in atm) are respectively :

Ammonia dissociates to give nitrogen and hydrogen . What happens if the pressure is increased on the system at equilibrium ?