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In the reaction, H2 +I2 hArr 2HI. In a 2...

In the reaction, `H_2 +I_2 hArr 2HI`. In a 2 litre flask 0.4 moles of each `H_2 and I_2` are taken. At equilibrium 0.5 moles of HI are formed. What will be the value of equilibrium constant, `K_c`

A

20.2

B

25.4

C

0.284

D

11.1

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(H_2, +, I_2, hArr, 2HI),(0.4 0.25 0.15//2,,0.4 0.25 0.15//2,,0.50//2):}`
`k_c =([HI]^2)/([H_2][I_2])=([(0.5)/2]^(2))/([(0.15)/2][(0.15)/2])=(0.5 xx0.5)/(0.15 xx0.15)=11.11`
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