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One mole of ethyl alcohol was treated wi...

One mole of ethyl alcohol was treated with one mole of acetic acid at `25^@C`. Two-third of the alcohol change into ester at equilibrium. The equilibrium constant for the reaction will be

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
`C_2H_5OH+CH_3COOH rarr CH_3COOC_2H_5 + H_2O`
`{:("Initial conc."," 1mol ","1 mol"," 0 mol"," 0 mol"),("At equilibrium",1-2/3=1/3"mol",1/3"mol",2/3"mol",1/3"mol"):}`
`K_C=(2/3 xx2/3)/(1/3 xx1/3)=4`
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