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Equilibrium constant for the reaction , ...

Equilibrium constant for the reaction , `N_(2) + 3 H_(2) hArr 2 NH_(3) ` is K, then equilibrium constant for the reaction, `NH_(3) hArr 1/2 N_(2) + 3/2 H_(2) ` will be ` ……….. .`

A

1/K

B

`1//K^2`

C

`sqrt(K)`

D

`1/sqrtK`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_1` for `N_2 +3H_2hArr 2NH_3`
`K_2` for `NH_3 hArr 1/2 N_2 +3/2H_2`
`K_1 = ([NH_3]^(2))/([N_2][H_2]^(3))xx([N_2]^(1//2)[H_2]^(3//2))/([NH_3])`
`K_1 xx K_2 =1/K_2 ,K_2 =1/sqrt(K_1)`
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