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NH(4)COONH(2)(s)hArr2NH(3)(g)+CO(2)(g) I...

`NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g)` If equilibrium pressure is 3 atm for the above reaction, then `K_(p)` for the reaction is

A

4

B

27

C

`4//27`

D

`1//27`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(NH_3) : P_(CO_2) =2:1`
`:. P_(NH_3) = 2"atm" , P_(CO_2) =1`
`K_p=[P_(NH_3)]^2.[P_(CO_2)]=2^2 xx1 =4`
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