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The equilibrium pressure for the reactio...

The equilibrium pressure for the reaction ` MSO_(4).2H_(2)O (s) hArr MSO_(4) (s) + 2H_(2)O (g) " is " pi //4 "atm at 400 K . The " K_(p) " for the given reaction ( in " atm^(2) ) ` is

A

`pi^2//4`

B

`pi//6`

C

`pi^2//16`

D

`pi//16`

Text Solution

Verified by Experts

The correct Answer is:
C
The given reaction is :
`MSO_(4) . 2H_2O_((s)) hArr MSO_(4(s)) + 2H_2O_((g))`
As the pressure is due to `H_2O_((g))` only hence,
`K_p = (p_(H_2O))^2 =(pi/4)^2=pi^2/16"atm"^2`
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