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One mole of a compound AB reacts with 1 ...

One mole of a compound AB reacts with 1 mole of a compound CD according to the equation `AB + CD hArr AD + CB`.
When equilibrium had been established it was found that `(3)/(4)` mole each of reactant AB and CD has been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

A

`9/16`

B

`1/9`

C

`16/9`

D

9

Text Solution

Verified by Experts

The correct Answer is:
D
`AB + CD hArr AD + CB`
`{:("Mole at t = 0", 1, 1, 0, 0),("Mole at equilibrium",(1-3/4),(1-3/4),(3/4),(3/4)),(,0.25,0.25,0.75,0.75):}`
`K_c=(0.75 xx0.75)/(0.25 xx0.25)=(0.5625)/(0.0625)=9`
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