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For the reaction C(s) +CO(2)(g) rarr 2CO...

For the reaction `C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63` atm at 100 K. If at equilibrium `p_(CO)=10p_(CO_(2)) ` then the total pressure of the gases at equilibrium is

A

6.3 atm

B

6.93 atm

C

0.63 atm

D

0.693 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`C_((s)) + CO_(2(g)) rarr 2CO_((g))`
Apply law of mass action,
`K_p =((P_(CO))^2)/(P_(CO_2))" or " 63= (10(P_(CO_2))^2)/(P_(CO_2))`
or 63 or ` 63= (10(P_(CO_2))^2)/(P_(CO_2))" or " 63 =100 P_(CO_2)`
`P_(CO_2)=63/100 =0.63 atm`
`P_(CO)=10P_(CO_2)=10xx0.63 =6.3` atm
`P_("Total") = P_(CO_2) +P_(CO) = 0.63 + 6.3 = 6.93` atm.
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