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A reaction is A+BhArrC+D. Initially we s...

A reaction is `A+BhArrC+D.` Initially we start with equal concentration of A and B. At equlibrium we find the moles of C is two times of A. What is the equilibrium constant of the reaction

A

4

B

2

C

`1//4`

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
A
`A+B hArr C+D`
`{:("At equilibrium ",a ,a ,2a ,2a):}`
`K = (2a xx2a)/(axxa) =4`
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