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3 moles of A and 4 moles of B are mixed ...

3 moles of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction.
`3A(g) + 4B(g) rarr 2C(g) + 3D(g)`
When equilibrium is reached, there is 1 mole of C. The equilibrium constant of the reaction is

A

`1/4`

B

`1/3`

C

`1/2`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
`3A +4B hArr 2C +3D`
`implies K_1 = ([C]^2[D]^3)/([A]^3[B]^4)" "...(i)`
When moles of C = 1, the equation becomes
`3/2 A +2B hArr C+(3)/2 D`
`implies K_2 = ([C][D]^(3//2))/([A]^(3//2)[B]^2)" "...(ii)`
On comparing Eq. (i) with Eq. (ii), we get
`K_2^2 = K_(1)` or `K_2 =(K_1)^(1//2)`
Hence, equilibrium extent `=1/2`
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