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A(g) + 3B(g) rarr 4C(g)Initially concent...

`A(g) + 3B(g) rarr 4C(g)`Initially concentration of A is equal to that of B. The equilibrium concentrations of A and C are equal. Kc is :

A

0.08

B

0.8

C

8

D

80

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(A,+,3B ,hArr,4C),(a,,b,,0),((a-x),,(b-3x),,4x):}`
`K_c=([C]^4)/([A][B]^3)=(4x.4x.4x.4x)/((a-x)(b-3x))`
Given a = b,
`a - x = 4x implies a = 5x = b`
`K_c = (4x.4x.4x.4x)/((5x-x)(5x-3x)^3)= (4x.4x.4x.4x)/(4x.2x.2x.2x)=8`
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