For reaction, PCl(3)(g)+Cl(2)(g) hArr ...

For reaction,
`PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g)`
the value of `K_(c)` at `250^(@)C` is 26. The value of `K_(p)` at this temperature will be .

A

`0.61 `

B

`0.57`

C

`0.83 `

D

`0.46`

Verified by Experts

The correct Answer is:

A

`K_p=K_c(RT)^(Deltan_g)=26(0.0821xx523)^(-1)=0.61`
`Deltan_g=1-2=-1`

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