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For the reversible reaction, N(2)(g) + 3...

For the reversible reaction, `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g)` At `500^(@)C` , the value of Kp is `1.44 xx 10^(-5)` when partial pressure is measured in atmosphere. The corresponding value of Kc with concentration in `mol//L` is:

A

`1.44 xx 10^(-5)//(0.082 xx 500)^(-2)`

B

`1.44 xx 10^(-5)//(8.314xx773)^(-2)`

C

`1.44 xx 10^(-5)//(0.082xx773)^2`

D

`1.44 xx 10^(-5)//(0.082 xx 773)^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(2) +3H_(2) hArr 2NH_3`
`Deltan = 2-4=-2`
`K_p =K_c(RT)^(Deltan_g) , K_p =K_c[RT]^(-2)`
`K_c=(K_p)/([RT]^(-2))=(1.44xx10^(-5))/([0.082xx773]^(-2))`
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