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At 500K, equilibrium constant, Kc for t...

At 500K, equilibrium constant, `K_c` for the following reaction is 5.
`1/(2) H_2(g) + 1/2I_(2)(g) hArr HI(g)`
What would be the equilibrium constant K. for the reaction `2HI(g) hArr H_2(g) +I_2(g)`

A

`0.04`

B

`0.4`

C

25

D

2.5

Text Solution

Verified by Experts

The correct Answer is:
A
For the reaction, `1/2H_(2)(g)+1/2I_(2)(g)hArrHI(g)`
`K_c=([HI])/([H_2]^(1//2)[I_2]^(1//2))=5`
Thus, for the reaction, `2HI(g) hArr H_(2)(g) +I_2(g)`
`K_(c_1)=([H_2][I_2])/([HI]^2)=(1/K_c)^2=(1/5)^2=1/25=0.04`
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