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For the reaction H(2)(g)+CO(g)hArrCO(g)...

For the reaction
`H_(2)(g)+CO(g)hArrCO(g)+H_(2)O(g),` if the initial concentration of`[H_(2)]=[CO_(2)]`and x moles /litres of hydrogen is consummed at equilibrium , the correct expression of `K_(p)` is :

A

`x^2/((1-x)^2)`

B

`((1+x)^2)/((1-x)^2)`

C

`x^2/((2+x)^2)`

D

`x^2/(1-x^2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2(g))+CO_(2(g))hArrCO_((g))+H_2O(g)`
`{:("Initial conc.",1,1,0,0),("At eqm.", (1– x) ,(1 – x) ,x, x):}`
`K_p=(p_(CO).p_(H_2O))/(p_(H_2).p_(CO_2))=(x.x)/((1-x)(1-x))=x^2/((1-x)^(2))`
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