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If alpha is the fraction of HI dissociat...

If `alpha` is the fraction of HI dissociated at equilibrium in the reaction, `2HI(g)hArrH_2(g)+I_2(g)` starting with the 2 moles of HI. Then the total number of moles of reactants and products at equilibrium are

A

1

B

2

C

`1+alpha`

D

`2+2alpha`

Text Solution

Verified by Experts

The correct Answer is:
B
`2HI hArr H_2 +I_2`
`{:("Initial moles",2,0,0),("At eqm.",2(1-alpha),alpha,alpha):}`
Total number of moles = 2.
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