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One mole of N(2)O(4)(g) at 300 K is kept...

One mole of `N_(2)O_(4)(g)` at 300 K is kept in a closed container under one atmosphere. It is heated to 600K when 20% by mass of `N_(2)O_(4)`(g) decomposes to `NO_(2)`(g). The resultant pressure is:

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The correct Answer is:
`2.4`
`N_(2) O_(2) hArr 2 NO_(2)`
` {:("Initial ", "1 Mole",),("At eqm. ",1 - 0.20,0.40"mole"),(,=0.80"mole","Total = 1.2 mole"):}`
1 mole vapour have pressure = 1 atm at 300 K
Applying ` PV = n RT, 1 xx V = 1 xx R xx 300` . . . (i)
When n = 1.2 mole, T = 600 K
`P xx V = 1.2 xx R xx 600` . . . (ii) Dividing (ii) by (i), P = 2.4 atm
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