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Equilivalent amounts of H(2) and I(2) ar...

Equilivalent amounts of `H_(2)` and `I_(2)` are heated in a closed vessel till equilibrium is obtained. If `80%` of the hydrogen is converted to `HI`, the `K_(c)` at this temperature is

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The correct Answer is:
64
`{:(,H_(2),I_(2),hArr,2HI),("Initial","a mol","a mol",,),("At eqm.",a - 0.8 a,a - 0.8 a,,2 xx 0.8 a ),(,= 0.2a,= 0.2a,,= 1.6 a),("Molar conc.",=(0.2a)/(V),(0.2a)/(V),,(1.6a)/(V)):}`
`J_(C) = ([HI]^(2))/([H_(2)][I_(2)]) = ((1.6 a // V)^(2))/((0.2 a// V) (0.2a // V))`
`= ((1.6)^(2))/((0.2)^(2)) = (2.56)/(0.04) = 64`
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