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Equimolar concentrations of H(2) and I(2...

Equimolar concentrations of `H_(2)` and `I_(2)` are heated to equilibrium in a 2 L flask. At equilibrium, the forward and backward rate constants are found to be equal. What percentage of initial concentration of `H_(2)` has reached at equilibrium ?

Text Solution

Verified by Experts

The correct Answer is:
`33.33`
`{:(,H_(2)(g),+,I_(2)(g),hArr,2HI(g)),("Initial","1 mol",,"1 mol",," 0"),("At eqm.",1 - x,,1 - x,," 2 x" ),("Molar conc.",(1-x)/(2),,(1-x)/(2),,(2x)/(2)"mil" L^(-1)):}`
`K = ((2 x)^(2))/((1 - x) (1 - x)) = ( 4 x^(2))/( (1 - x)^(2))`
But `k_(f) // k = 1 rArr k = 1 :. (2 x)/( 1 - x) = 1 or x = 1// 3`
Percent dissociation = 100 / 3 = 33.33% .
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