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What is the equilibrium expression for t...

What is the equilibrium expression for the reaction`P_(4)(s)+50_(2)(g)hArrP_(4)O_(10)(s)`

A

`K_(c) = [O_(2)]^(5)`

B

`K_(c) = [P_(4) O_(10)]// 5 [P_(4)] [O_(2)]`

C

`K_(c) = [P_(4) O_(10)]// [P_(4)] [O_(2)]^(5)`

D

`K_(c) = 1 // [O_(2)]^(5)`

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(4_((s))) + 5 O_(2_((g))) hArr P_(4) O_(10_((s)))`
`K_(c) = ([P_(4) O_(10_((s)))])/([P_(4_((s)))][O_(2_((g)))]^(5))`
We know that concentration of a solid component is always taken as unity `K_(c) = (1)/([O_(2)]^(5))`
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