The equilibrium constant for the reaction
`N_(2)(g)+O_(2)(g) hArr 2NO(g)`
at temperature T is `4xx10^(-4)`.
The value of `K_(c)` for the reaction
`NO(g) hArr 1/2 N_(2)(g)+1/2 O_(2)(g)`
at the same temperature is

Options

A. `4 xx 10^(-4)`
B. 50
C. `2 . 5 xx 10^(2)`
D. `0.02`

Answer

B

Explanation

`N_(2) (g) + O_(2) (g) hArr 2 NO (g) K = 4 xx 10 ^(-4)`
`2 NO (g) hArr N_(2) (g) + O_(2) (g) K. = 1//K`
` NO (g) hArr (1)/(2) N_(2) (g) + (1)/(2) O_(2) (g) K_(C) = (K.) ^(1//2) `
`K_(C) = (1)/((4 xx 10 ^(-4))^(1//2)) = (1)/(2 xx 10 ^(-2)) = 50 `