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A vessel at 1000 K contains CO2 with a ...

A vessel at 1000 K contains `CO_2` with a pressure of 0.5 atm. Some of the `CO_2` is converted to CO on addition of graphite. Calculate the value of K, if the total pressure at equilibrium is 0.8 atm.

A

1.8 atm

B

3 atm

C

0.3 atm

D

`0.18` atm

Text Solution

Verified by Experts

The correct Answer is:
A
` CO_(2_((g))) + C_((g)) hArr 2 CO_((g))`
`{:("0.5 atm"),("0.5 - p 2p"):}`
Total pressure =0.5 – p+2p=0.8
P = 0.3
`K_(p) = (P_(CO)^(2))/(P_(CO_(2))) = ((2p)^(2))/((0.5 - p)) = ((0.6)^(2))/((0.5 - 0.3))`
`K_(p) = 1.8`
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