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Consider the reaction N(2)(g) + 3H(2)(g)...

Consider the reaction `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g)`
The equilibrium constant of the above reaction is `K_(p)` If pure ammonia is left to dissociated, the partial pressure of ammonia at equilibrium is given by : (Assume that `P_(NH_(3)) lt lt P_(total)` at equilibrium)

A

`(3 ^((3)/(2)) K_(P)^(1//2) P^(2))/(16)`

B

`(3 ^((3)/(2)) K_(p)^(1//2) P^(2))/(4)`

C

`(K_(p)^(1//2) P^(2))/(4)`

D

`(K_(p)^(1//2)P^(2))/(16)`

Text Solution

Verified by Experts

The correct Answer is:
A
`2 NH_(3) hArr N_(2) + 3H_(2) K._(P) = (1)/(K_(P))`
`P_("total") = P = P_(N_(2)) + H_(2) + P_(NH_(3))+ P_(N_(2)) + P_(H_(2))`
`P_(N_(2)) = (P)/(4)`
`P_(H_(2)) = (3P)/(4)`
`(1)/(K_(P)) = (((P)/(4))((3P)/(4))^(3))/((P_(NH_(3)))^(2))`
`P_(NH_(3)) = (3^((3)/(2))P^(2))/(16) (K_(P))^(1//2)`
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