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For the equilibrium, 2H(2)O hArr H(3)...

For the equilibrium,
`2H_(2)O hArr H_(3)O^(+) + OH^(-)`,the value of `DeltaG^(@)`at 298 K is approximately:

A

80 kJ `mol^(-1)`

B

`-100 kJ mol^(-1)`

C

`- 80 kJ mol^(-1)`

D

100 kJ `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta G^(@) = - 2.303` RT log K
`= - 2.303 xx 8.314 xx 298 log (10^(-14))`
`= + 80 (kJ)/(mol)`
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