Home
Class 11
CHEMISTRY
2SO3 (g) + O2 (g) hArr 2SO3 (g) In an...

`2SO_3 (g) + O_2 (g) hArr 2SO_3 (g)`
In an equilibrium mixture, the partial pressures are
`P_(SO_3) = 43 kPa , P_(O_2) = 530 ` Pa and `P_(SO_2) = 45 ` kPa. The equilibrium constant `K_p` = _______ `xx 10^(-2)` (nearest integer)

Text Solution

Verified by Experts

The correct Answer is:
172
`2 SO_(2) (g) + O_(2) (g) hArr 2SO_(3) (g)`
`K_(p) = (P_(SO_(3))^(2))/(P_(SO_(2))^(2)P_(O_(2)))`
`= ((43)^(2))/( (0.53)(45)^(2))`
`= 1.7228 k Pa^(-1)`
`~~ 172 xx 10 ^(-2) k Pa^(-1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

When the reaction, 2NO_(2)(g) hArr N_(2)O_(4)(g) reaches equilibrium at 298 K . The partial pressure of NO_(2) and N_(2)O_(4) are 0.2 Kpa and 0.4 Kpa , respectively. What is the equilibrium constant K_(p) of the above reaction at 298 K ?

2 SO _(2) (g)+ O _(2) (g) to 2 SO _(3) (g) The above reaction is carried out in a vessel starting with partial pressure P _( SO _(2)) = 250 m bar P _( O _(2)) = 750 m bar and P _( SO _(3)) = 0 bar . When the reaction is complete, the total pressure in the reaction vessel is _____ m bar. (Round off to the nearest integer)

The equilibrium constant for the reaction A (s) hArr M (s) + (1)/(2) O _(2) (g) is K _(P) = 4. At equilibrium, the partial pressrue of O _(2) is __________ atm. (Round off to the nearest integer)

The value of K_p for the reaction, 2SO_2(g)+O_2(g) hArr 2SO_3(g) is 5 what will be the partial pressure of O_2 at equilibrium when equal moles of SO_2 and SO_3 are present at equilibrium ?

A(s) harr M(s) + 1/2O_2(g) K_p of the reaction is 4. Find the partial pressure of O_2 at equilibrium

The equilibrium constant for the reaction 2SO_(2(g)) + O_(2(g)) rarr 2SO_(3(g)) is 5. If the equilibrium mixture contains equal moles of SO_(3) and SO_(2) , the equilibrium partial pressure of O_(2) gas is

At equilibrium degree of dissociation of SO_(3) is 50% for the reaction 2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g) . The equilibrium constant for the reaction is

In the equilibrium 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g) , the partial pressure of SO_(2),O_(2) and SO_(3) are 0.662,0.10 and 0.331 atm respectively . What should be the partial pressure of Oxygen so that the equilibrium concentrations of SO_(3) are equal ?

Find the value of K_(p) for the reaction : 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g) , if the partial pressures of SO_(2), O_(2) , and SO_(3) are 0.559 atm, 0.101 atm and 0.331 atm respectively. What will be the partial pressure of O_(2) gas if at equilibrium, equal amounts (in moles) of SO_(2) and SO_(3) are observed?

For the following equilibrium, 2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g) the total equilibrium pressure is P_(1) . If volume of the system is reduced to 1//2 of this initial volume then equilibrium is restablished. The new equilibrium total pressure will be :