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If alpha is the degree of ionization, C ...

If `alpha` is the degree of ionization, C the concentration of a weak electrolyte and `K_(a)` the acid ionization constant , then the correct relationship between `alpha` and C is

A

`alpha^(2) = sqrt((K_(a))/C)`

B

`alpha^(2) = sqrt(C/(K_(a)))`

C

`alpha = sqrt((K_(a))/C)`

D

`alpha = sqrt(C/(K_(a)))`

Text Solution

Verified by Experts

The correct Answer is:
C
According to the Ostwald’s dilution formula `alpha^(2) = (K(a-alpha))/C` .. But for weak electrolytes `alpha` is very small. So that `(1-alpha)` can be neglected . So that `alpha = sqrt((K_(a))/C)`.
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