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The dissocication constant of a weak aci...

The dissocication constant of a weak acid is `1.0xx10^(-5)`, the equilibrium constant for the reaction with strong base is

A

`1.0 xx 10^(-5)`

B

`1.0 xx 10^(-9)`

C

`1.0 xx 10^(9)`

D

`1.0 xx 10^(14)`

Text Solution

Verified by Experts

The correct Answer is:
C
`HA hArr H^(+) +A^(-), K_(a) = ([H^(+)][A^(-)])/([HA])" "....(i)`
neutralization of the weak acid with strong base is
`HA +OH^(-) hArrA^(-) +H_(2)O`
`K = ([A^(-)])/([HA][OH^(-)])" "....(ii)`
Dividing (i) by (ii) `(K_(a))/K = [H^(+)] [OH^(-)] =K_(w)=10^(-14)`
`K = (K_(a))/(K_(w))=(10^(-5))/(10^(-14)) = 10^(9)`
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