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Solubility of BaF(2) in a solution of Ba...

Solubility of `BaF_(2)` in a solution of `Ba(NO_(3))_(2)`, will be represented by the concentration term:

A

`[Ba^(++)]`

B

`[F^(-)]`

C

`1/2 [F^(-)]`

D

`2[NO_(3)^(-)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`Ba(NO_(3))_(2) hArr underset ((S_(1)))(Ba^(2+)) + underset (2S_(2))(2NO_(3)^(-)) `
Due to common ion `[Ba^(2+)]` , the solubility of `BaF_(2)` will be reduced say `S_(2)`
`BaF_(2)hArr underset ((S_(1)+S_(2)))(Ba^(2+)) + underset (2S_(2)) (2F^(-))`
Hence `S_(2) = 1/2 [F^(-1)]`
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