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The solubility product constant K(sp) of...

The solubility product constant `K_(sp)` of `Mg(OH)_(2)` is `9.0 xx 10^(-12)`. If a solution is 0.010 M with respect to `Mg^(2+)` ion, what is the maximum hydroxide ion concentration which could be present without causing the precipitation of `Mg(OH)_(2)`

A

`1.5 xx 10^(-7)`M

B

`3.0 xx 10^(-7)` M

C

`1.5 xx 10^(-5)` M

D

`3.0 xx 10^(-5)` M

Text Solution

Verified by Experts

The correct Answer is:
D
`underset (K_(sp))(Mg(OH)_(2))hArr underset (S)(Mg^(++))+ underset((2S)^(2))(2OH^(-))`
`K_(sp)= S xx 4S^(2)`
`(K_(sp))/(Sxx4) =S^(2) = (9xx10^(-12))/(0.010xx4) = 2.25 xx10^(-10)`
`S = sqrt(2.25 xx10^(-10))=1.5 xx10^(-5)`m/L
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