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In the reaction: H(2)S hArr 2H^(+) + S^(...

In the reaction: `H_(2)S hArr 2H^(+) + S^(-)`, when `NH_(4)OH` is added, then

A

`S^(--)` is precipitate

B

No action takes places

C

Concentration of `S^(--)` decreases

D

Concentration of `S^(--)` increases

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)S hArr 2H^(+) +S^(--)`
`NH_(4)OH hArr NH_(4)^(+) +OH^(-)`
The `OH^(-)` ion of `NH_(4)OH` will react with `H^(+)` ion from `H_(2)S` .
`H^(+) +OH^(-) hArr H_(2)O `
So concentration of `H^(+)` ion will decrease and by Le–chatelier principle, the reaction will move in the forward direction and more `S^(--)` ions will form.
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