Home
Class 11
CHEMISTRY
On adding 0.1 M solution each of Ag^(+),...

On adding 0.1 M solution each of `Ag^(+),Ba^(2+), Ca^(2+)` ions in a `Na_(2)SO_(4)` solution, species first precipitated is `(K_(sp)BaSO_(4)=10^(-11),K_(sp)CaSO_(4)=10^(-6),K_(sp) Ag_(2)SO_(4)=10^(-5))`

A

`Ag_(2)SO_(4)`

B

`BaSO_(4)`

C

`CaSO_(4)`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
B

Solubility of `BaSO_(4) (x) = sqrt(K_(sp)) = sqrt(10^(-11))`
= `3.16 xx10^(-6) ` mol/L
Solubility of `CaSO_(4) (x) = sqrt(K_(sp)) = sqrt(10^(-6))`
`= 1.0 xx 10^(-3) ` mol/L
Solubility of `Ag_(2)SO_(4) = root3 ((K_(sp))/4)`
`( :. " for " Ag_(2)SO_(4),4x^(3)K_(sp)) =root 3(10^(-5)/4) = 1 xx 10^(-2) `
Least solubility is of `BaSO_(4)` , hence it will precipitate first .
Promotional Banner

Similar Questions

Explore conceptually related problems

Equal volumes of 0.02M CaC1_(2) and 0.0004M Na_(2)SO_(4) are mixed. Will a precipitate from? K_(sp) for CaSO_(4) = 2.4 xx 10^(-5) ?

a. Equal volumes of 0.02M CaC1_(2) and 0.04M Na_(2)SO_(4) are mixed. Will a precipitate form? K_(sp) of CaSO_(4) = 2.4 xx 10^(-5)

If a solution contains 10^(-6)M each of X^(-),Y^(-2) and Z^(3-) ions, than upon addition of AgNO_(3)(s) slowly to the above solution with striing : ( Given : K_(sp)(AgX)=9xx10^(-14),K_(sp)(Ag_(2)Y)=4.9xx10^(-21),K_(sp)(Ag_(3)Z)=5.12xx10^(-29))

Solubility of Ag_(2)CrO_(4) ( K_(sp)=4xx10^(-13) ) in 0.1 M K_(2)CrO_(4) solution will be :

A solution is 0.10 M Ba(NO_(3))_(2) and 0.10 M Sr(NO_(3))_(2.) If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)] when SrCrO_(4) begins to precipitate? [K_(sp)(BaCrO_(4))=1.2xx10^(-10),K_(sp)(SrCrO_(4))=3.5xx10^(-5)]

The solubility of PbSO_(4) in 0.1M Na_(2)SO_(4) solution is ( K_(sp) of PbSO_(4) is 1.25 xx 10^(-9) )